Imma juss solve question r
Using Pythagoras, 13^2 = 5^2 + |BC|^2
Therefore, 169 = 25 + |BC|^2
then, 144 = |BC|^2
so |BC| is 12cm (root of 144)
To find AC which is marked r, substituting BC as 12 and AB as 5, we can also use Pythagoras' Theorem to solve
Therefore, 12^2 = 5^2 + r^2
144 = 25 + r^2
r^2 = 144 - 25
r^2 = 119 and r = √119 = 10.9 or 11
