Respuesta :
Step-by-step explanation:
If sine theta is 3/5, taking the sine inverse will give you 36.87°.
4tan theta is 4 × tan36.87 = 3
3sin theta = 3 × sin36.87 = 1.8
6cos theta is 6× cos36.87 = 4.8
Therefore, it becomes 3 + 1.8 - 4.8 = 4.8 - 4.8
The answer is 0
Answer:
[tex] \boxed{\sf 0} [/tex]
Given:
[tex] \sf sin \theta = \frac{3}{5} [/tex]
To Find:
[tex] \sf 4tan \theta + 3sin \theta - 6cos \theta[/tex]
Step-by-step explanation:
[tex]\sf As \ we \ know, \\ \sf sin 37 \degree = \frac{3}{5} \\ \\ \sf \therefore \ sin \theta = sin 37 \degree \\ \\ \sf \implies \theta = 37 \degree[/tex]
[tex]\sf \implies tan \theta = \frac{3}{4} \\ \\ \sf \implies cos \theta = \frac{4}{5}
[/tex]
[tex]\sf So, \\ \sf \implies 4tan \theta + 3sin \theta - 6cos \theta \\ \\ \sf Putting \ the \ values \ of \ tan \theta , sin \theta \ and \ cos \theta \ respectively: \\ \sf \implies ( 4 \times \frac{3}{ 4}) + (3 \times \frac{3}{5}) - (6 \times \frac{4}{5} ) \\ \\ 4 \times \frac{3}{ 4} = 3: \\ \sf \implies \boxed{3} + (3 \times\frac{3}{5}) - (6 \times \frac{4}{5} ) \\ \\ \sf 3 \times 3 = 9: \\ 3 + \frac{\boxed{9}}{5} - (6 \times \frac{4}{5} ) \\ \\ \sf 6 \times 4 = 24: \\ \sf 3 + \frac{9}{5} - \frac{\boxed{24}}{5} \\ \\ \sf Put \ 3 + \frac{9}{5} - \frac{24}{5} \ over \ the \ common \ denominator \ 5: \\ \sf \implies 3 \times \frac{5}{5} + \frac{9}{5} - \frac{24}{5} \\ \\ \sf \implies \frac{15}{5} + \frac{9}{5} - \frac{24}{5} \\ \\\sf \implies \frac{15 + 9 - 24}{5} \\ \\ \sf 15 + 9 = 24: \\ \sf \implies \frac{\boxed{24} - 24}{5} \\ \\ \sf 24 - 24 = 0: \\ \sf \implies \frac{\boxed{0}}{5} \\ \\ \sf \implies 0 [/tex]