Answer:
sin θ = [tex]\frac{\sqrt{65} }{9}[/tex].
Step-by-step explanation:
Remember that:
sec θ is the reciprocal of cos θ. Therefore:
cos θ = -4/9.
From this, we can derive that:
Adjacent side = -4.
Hypotenuse = 9
Use the Pythagorean Theorem to solve for the 'Opposite' side:
9² = (-4)² + b²
81 = 16 + b²
65 = b²
b = √65
sin θ = O/H, so:
sin θ = [tex]\frac{\sqrt{65} }{9}[/tex]
