A rectangle with perimeter 18 cm has a length that is 3 cm more than twice its width. Find the dimensions of the rectangle. SOLVE EACH APPLICATION USING ALGEBRA. TYPE THE EQUATION OR INEQUALITY AND PLEASE SHOW WORK.

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Answer:

Length = 7 cm

Width = 2 cm

Step-by-step explanation:

Perimeter of rectangle = 18 cm

Let length of rectangle = [tex]l[/tex] cm

Let width of rectangle =  [tex]w[/tex] cm

As per given statement, length is 3 cm more than the twice of its width:

Writing equation:

[tex]l = 2\times w +3 ....... (1)[/tex]

Formula for perimeter of a rectangle is given as:

[tex]P = 2 \times (Length + Width)[/tex]

OR

[tex]P = 2 \times (l + w)[/tex]

Putting values of P as given and [tex]l[/tex] by using equation (1):

[tex]18 = 2 \times (2w +3 + w)\\\Rightarrow \dfrac{18}2 = 3w +3 \\\Rightarrow 9 = 3w +3\\\Rightarrow 3w = 9 -3\\\Rightarrow w = \dfrac{6}{3}\\\Rightarrow w = 2\ cm[/tex]

Putting value of [tex]w[/tex] in equation (1):

[tex]l = 2\times 2 +3 \\\Rightarrow l = 4+3\\\Rightarrow l = 7\ cm[/tex]

So, the dimensions are:

Length = 7 cm

Width = 2 cm

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