Question

FAST PLEASE
What is the surface area of the triangular prism? A triangular prism. The base is 6 feet by 9 feet. The 2 rectangular sides are 9 feet by 5 feet. The triangular sides have a base of 6 feet and height of 4 feet. square feet

Answer 1

Answer:

A ≈ 208.28

Step-by-step explanation:

A ≈ 208.28

a Base side 6

b Base side 9

c Base side 5

h Height         9

Now you have to use the formulas:

A = 2$A_{B}$ + (a+b+c) h

$A_{B}$ = √ s (s﹣a) (s﹣b) (s﹣c)

s =  $\frac{a + b + c}{2}$

Solving for A:

A = a h + b h + c h + $\frac{1}{2}$﹣√ $a^{4}$ + $2(ab)^{2}$ +  $2(ac)^{2}$ ﹣ $b^{4}$ + $2(bc)^{2}$﹣$c^{4}$

= 6 · 9 + 9 · 9 + 5 · 9 + $\frac{1}{2}$ · √﹣$6^{4\\}$ + 2 · $(6*9)^{2}$ + 2 · $(6*5)^{2}$﹣$9^{4}$ + 2 · $(9*5)^{2}$ ﹣$5^{4}$

≈ 208.28427

Answer 2

Answer:

SA = 169 feet

Step-by-step explanation:

Surface Area of triangular prism = b₁h₁+2b₂h₂ + b₃h₃

Where b₁ is the base of triangular side(6 ft), h₁ is the height of triangular side (4 ft), b₂ is the base of rectangular side (9 ft), h₂ is the height of rectangular side(5 ft), b₃ is the base of the base(6 ft), h₃ is the height of the base(4 ft).

SA = $(6*4)+2(9*5)+(6*9)$

SA = 24+90+54

SA = 169 feet