Answer:
Angle of depression from C to T measures approximately [tex]20.52^o[/tex]
Step-by-step explanation:
To start, we use triangle DTA to find the length of the side AT, making use of the tangent function:
[tex]tan(23^o)=\frac{AT}{28\,m} \\AT=tan(23^o)\,* 28\,m\\AT=11.89\,m[/tex]
Now we need to find the size of the rectangular land diagonal:
[tex]diagonal=\sqrt{28^2+15^2}=31.76\,m[/tex]
With this information, we can now find the measure of angle "C" (depression angle from C to T), using the triangle ACT:
[tex]tan(C)=\frac{opposite}{adjacent} \\tan(C)=\frac{11.89}{31.76}\\C=arctan(\frac{11.89}{31.76})\\C=20.52^o[/tex]
