Answer:
Answer choice 3
Step-by-step explanation:
Option 3 is correct one
∠TQS ≅ ∠RSQ
⇒ ΔTQS ≅ ΔRSQ
⇒ QR≅ST and QT≅RS
QRST is parallelogram by definition
Option 3
Angle TQS is congruent to angle RSQ and can be proved by alternating interior angle theorem.
Triangle TQS is congruent to triangle RSQ.
Line QR is congruent to line ST.
Line QT is congruent to line RS.
