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Answer:
(B)[tex]m\angle FEH=230^\circ[/tex]
Step-by-step explanation:
We know that the External Angle = Half the Difference of the Two Arcs
Therefore:
Since FGH is the exterior angle and FEH and FH are the two arcs, then:
[tex]\dfrac12 (\angle FEH-\angle FH)=50^\circ\\\\\angle FEH- \angle FH=100^\circ[/tex]
Also:
[tex]\angle FEH+ \angle FH=360^\circ[/tex]
Adding the two equations, we have:
[tex]\angle FEH- \angle FH+(\angle FEH+ \angle FH)=360^\circ+100^\circ\\2\angle FEH=460^\circ\\$Divide both sides by 2\\Therefore\\m\angle FEH=230^\circ[/tex]