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  • 130°
  • 230°
  • 260°
  • 310°

Answer:

(B)[tex]m\angle FEH=230^\circ[/tex]

Step-by-step explanation:

We know that the External Angle = Half the Difference of the Two Arcs

Therefore:

Since FGH is the exterior angle and FEH and FH are the two arcs, then:

[tex]\dfrac12 (\angle FEH-\angle FH)=50^\circ\\\\\angle FEH- \angle FH=100^\circ[/tex]

Also:

[tex]\angle FEH+ \angle FH=360^\circ[/tex]

Adding the two equations, we have:

[tex]\angle FEH- \angle FH+(\angle FEH+ \angle FH)=360^\circ+100^\circ\\2\angle FEH=460^\circ\\$Divide both sides by 2\\Therefore\\m\angle FEH=230^\circ[/tex]

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