Question

How many grams of AgNO3 are needed to make 250 ml of a solution that is 0.135 M

Answer 1

Answer:

( About ) 5.7 grams

Explanation:

Take a look at the attachment below for a proper explanation;

Answer 2

5.605 grams of AgNO₃ are needed to make 250 ml of a solution that is 0.135 M.

Given:

Molarity= 0.135 M

Volume= 250mL

Mass=?

Molarity:

It is the concentration of a solution measured as the number of moles of solute per liter of solution.

$M=\frac{n}{V}$

where, n= number of moles of solute and V= volume

On putting the given values in formula we will get;

$0.135 molL^{-1}=\frac{n}{0.25 L} \\\\n= 0.135* 0.25=0.033\\\\n= 0.033 moles$

In order to find the grams of AgNO₃:

Molar mass of AgNO₃= 169.87 g/mol

Number of moles= $\frac{\text{Given mass}}{\text{Molar mass}}$

Substituting the values in the above formula, we will get the mass of AgNO₃

$0.033=\frac{\text{Given mass}}{169.87} \\\\\text{Given mass}= 0.033*169.87= 5.605 g$

So, 5.605 grams of AgNO₃ are needed to make 250 ml of a solution that is 0.135 M.

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