Respuesta :
Answer:
( About ) 5.7 grams
Explanation:
Take a look at the attachment below for a proper explanation;

5.605 grams of AgNO₃ are needed to make 250 ml of a solution that is 0.135 M.
Given:
Molarity= 0.135 M
Volume= 250mL
Mass=?
Molarity:
It is the concentration of a solution measured as the number of moles of solute per liter of solution.
[tex]M=\frac{n}{V}[/tex]
where, n= number of moles of solute and V= volume
On putting the given values in formula we will get;
[tex]0.135 molL^{-1}=\frac{n}{0.25 L} \\\\n= 0.135* 0.25=0.033\\\\n= 0.033 moles[/tex]
In order to find the grams of AgNO₃:
Molar mass of AgNO₃= 169.87 g/mol
Number of moles= [tex]\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Substituting the values in the above formula, we will get the mass of AgNO₃
[tex]0.033=\frac{\text{Given mass}}{169.87} \\\\\text{Given mass}= 0.033*169.87= 5.605 g[/tex]
So, 5.605 grams of AgNO₃ are needed to make 250 ml of a solution that is 0.135 M.
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