Question

What is the period of y = 2cos(3x—2pi)
a.3pi
b.6pi
c.3pi-2
d.2pi/3​

Answer 1

Answer:

d.2pi/3​

Step-by-step explanation:

Suppose we have a cosine function in the following format:

$y = a\cos{bx + c}$

Only b is relevant to find the period.

The period is: $P = \frac{2\pi}{|B|}$

In this question:

$y = 2\cos{3x - 2\pi}$

Then B = 3.

$P = \frac{2\pi}{|B|} = \frac{2\pi}{|3|} = \frac{2\pi}{3}$

So the correct answer is:

d.2pi/3​