Answer:
Expected value of the sampling distribution of P^:
E(p^) = p=0.8
Standard Error(SE) of the Sample Proportion:
√ (p(1-p) / n)=√ (0.8(1-0.8) / 50)=0.0693
Step-by-step explanation:
If you have a large enough sample size, you can use the normal distribution for the sampling distribution of p^.
How large is “large enough”? Use these formulas for a general guideline:
nPp^≥5
n(1-p^)≥5.
Here
50*0.8=40>5
50*(1-0.8)=10>5
Both are above 5, so we can use the normal distribution.
Expected value of the sampling distribution of P^:
E(p^) = p=0.8
Standard Error(SE) of the Sample Proportion:
√ (p(1-p) / n)=√ (0.8(1-0.8) / 50)=0.0693
Hope this will be helpful. Thank and God Bless You :)
