Question

Find the equation of the circle whose center and radius are given.
center (7.-3), radius = 7

Answer 1

Answer:

(x - 7)² + (y + 3)² = 7

Step-by-step explanation:

The equation of a circle is denoted by: $(x -x_1)^2+(y-y_1)^2=r^2$, where $(x_1,y_1)$ is the centre and r is the radius.

Here, the centre is (7, -3), which means $x_1=7$ and $y_1=-3$. The radius is r = √7. Plug these values into the formula:

$(x -x_1)^2+(y-y_1)^2=r^2$

$(x -7)^2+(y-(-3))^2=(\sqrt{7}) ^2$

$(x -7)^2+(y+3)^2=7$

Thus, the answer is (x - 7)² + (y + 3)² = 7.

~ an aesthetics lover