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27-06-2020
Mathematics

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The remainder when 2x^2-x-5 divided by (x-3) is

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mhanifa mhanifa

27-06-2020

Answer:

10

Step-by-step explanation:

2x^2-x-5= 2x^2-6x + 5x -15 +10= 2x(x-3) +5(x-3) + 10= (2x+5)(x-3) + 10

(2x^2-x-5)/(x-3)= 2x+5 + 10/(x-3)

So the remainder is 10

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