Question

Can anyone help me with this answer:
One of the zeroes of the polynomial 2x2 + 7x –4 is
(A) 2
(B)1/2
(C) -1/2
(D) –2

Answer 1

Answer:

Option B

Step-by-step explanation:

For this we'll put all of these options in place of x

Number 1:

=> $2(2)^2+7(2)-4$

=> 2(4)+14-4

=> 8+10

=> 18

So, This is not the zero of the polynomial

Number 2:

=> $2(1/2)^2+7(1/2)-4$

=> 2(1/4)+7/2-4

=> 1/2+7/2-4

=> $\frac{1+7-8}{2}$

=> $\frac{8-8}{2}$

=> 0

Yes, This is the zero of the polynomial having zero as an answer

So, We'll end the solution here because we have found the zero of the polynomial.

Hope this helps :)