Question

A block slides down a ramp with friction. The friction experienced by the block is 21 N. The mass of the block is 8 kg. The ramp is 6 meters long (meaning, the block slides across 6 meters of ramp with friction). The block is originally 2 meters vertically above the ground (the bottom of the ramp). What is the change in energy of the block due to friction, expressed in Joules

Answer 1

Complete Question

The complete question is shown on the first uploaded image

Answer:

the change in energy of the block due to friction is  $E = -126 \ J$

Explanation:

From the question we are told that

    The  frictional force is  $F_f = 21 \ N$

    The mass of the block is  $m_b = 8 \ kg$

    The length of the ramp is  $l = 6 \ m$

    The height of the block is  $h = 2 \ m$

The change in energy of the block due to friction is mathematically represented as

     $\Delta E = - F_s * l$

The negative sign is to show that the frictional force is acting against the direction of the block movement

  Now substituting values

      $\Delta E = -(21)* 6$

      $\Delta E = -126 \ J$