Determine the intercepts of the line. 2x+5y=-62x+5y=−62, x, plus, 5, y, equals, minus, 6 yyy-intercept: \Big((left parenthesis ,,comma \Big))right parenthesis xxx-intercept: \Big((left parenthesis ,,comma \Big))right parenthesis

Respuesta :

Answer:

x  intercept  a = - 3

y - intercept [tex]b = \frac{-6}{5}[/tex]

The  intercept form of the line equation is

 [tex]\frac{x}{-3} + \frac{y}{\frac{-6}{5} } = 1[/tex]  

Step-by-step explanation:

Explanation:-

Given straight line 2 x + 5 y = - 6  

Dividing ' -6' on both sides , we get

     [tex]\frac{2x}{-6} + \frac{5y}{-6} = 1[/tex]

on simplification , we get

   [tex]\frac{x}{-3} + \frac{y}{\frac{-6}{5} } = 1[/tex]

The intercept form is  

    [tex]\frac{x}{a} + \frac{y}{b} = 1[/tex]

x  intercept  a = - 3

y - intercept [tex]b = \frac{-6}{5}[/tex]

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