Homework help, one of the few I have

Answer:
x=4 and the solution is not extraneous
Step-by-step explanation:
[tex]\sqrt{2x+1}=3 \\\\2x+1=9 \\\\2x=8 \\\\x=4[/tex]
This solution is not extraneous, because plugging it back in you get:
[tex]\sqrt{2(4)+1}=3 \\\\\sqrt{9}=3 \\\\3=3[/tex]
Hope this helps!
Answer:
X = 4, solution is not extraneous
Step-by-step explanation:
3 = √9
so we get the following comparison;
2X + 1 = 9 (both minus 1)
2X = 8 (divide by 2)
X = 4
if we fill in 4 for X. we get
√2•4+ 1 = √9 = 3 so the solution is not extraneous