Answer:
Please red the answer below
Step-by-step explanation:
In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.
For the x component you have:
[tex]T_1cos\theta_1-T_2cos\theta_2=0[/tex] (1)
T1: tension of the first cable = 1500N
T2: tension of the second cable = 800N
θ1: angle between the horizontal and the first cable
θ2: angle between the horizontal and the first cable
For the y component you have:
[tex]T_1sin\theta_1+T_2sin\theta_2-W=0[/tex] (2)
W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N
You can squared both equations (1) and (2) and the sum the two equations:
[tex]T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2[/tex]
Then, you sum the equations:
[tex]T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2[/tex] (3)
Next, you use the following identity:
[tex]sin^2\theta+cos^2\theta=1[/tex]
and you obtain in the equation (3):
[tex]T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°[/tex]
With this values you can calculate the value of the another angle, by using the equation (1):
[tex]\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°[/tex]
Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:
[tex]l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\[/tex]
d: distance to the right side of the field
By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.