Data kept by the human resources department of a manufacturing company indicates that t hours after beginning work, the production P (in units completed) of an average worker changes at the rate of P ' ( t ) = 0.1 ( t + 2 ) √ t 2 + 4 t If 2 hours after beginning work, an average worker can complete 14 . Round all answers to 2 decimal places. a . Specify the function that describes the number of units an average worker can complete in terms of the number of hours after beginning work. P ( t ) = b . Find the number of units an average worker can complete 2 hours after beginning work. units c . Approximate the number of units an average worker can complete from hour 4 to hour 5 . about units

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Answer:

a)   [tex]P(t)=0.1\,\sqrt{t^2+4t} +13.65[/tex]

b)  P(2) = 14 units

c) from hour 4 to hour 5, an average worker can complete about 0.1 of a unit.

Step-by-step explanation:

Notice that the problem gives the derivative of the production function, and also an extra piece of information (P(2) = 14) - also called initial condition - that allows us to find the actual production with any additional constant.

Let's work on the "antiderivative" of the function:

[tex]P'(t)= \frac{0.1\,(t+2)}{\sqrt{t^2+4t} }[/tex]

Using the change of variables  [tex]u=\sqrt{t^2+4t}[/tex] , [tex]du[/tex]  becomes [tex]\frac{1}{2}\frac{\,2\,(t+2)}{\sqrt{t^2+4t} }[/tex]

Then, the family of antiderivatives becomes:

[tex]P(t)=0.1\,\sqrt{t^2+4t} +C[/tex]

We should be able to determine the constant C using the initial condition for the problem: [tex]P(2)=14[/tex]

Then we evaluate:

[tex]P(2)=0.1\,\sqrt{2^2+4*2} +C\\14=0.1\,\sqrt{12} +C\\C=14-0.1\,\sqrt{12} \\C=14-0.35\\C=13.65[/tex]

Then the function requested in point a) is:

[tex]P(t)=0.1\,\sqrt{t^2+4t} +13.65[/tex]

Point b) "Find the number of units an average worker can complete 2 hours after beginning work" was already given as the initial condition, so P(2) = 14 units.

Point c) asks for the number of units an average worker can complete from hour 4 to hour 5, so we calculate the difference:

[tex]P(5)-P(4)=14.32 - 14.22= 0.10\,\, units[/tex]

So the average worker can complete one tenths of a unit between hour 4 and hour 5.

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