Question

Which function has a vertex on the y-axis?
O f(x) = (x - 2)^2
O f(x) = x(x + 2)
O f(X) = (x-2) (x+2)
O f(X) = (x + 1) (x - 2)

Answer 1

Answer:

(x-2)(x+2)

Step-by-step explanation:

• first:  the function that represent on graph as a curve  with vertex it must be a quadratic function of second degree, so we have here  3 equation of second degree which are after simplifying will be :

$x^{2} - 4x+4$

$x^{2} - 4$

$x^{2} -x -2$

• Second if the vertex of curve is on Y axis therefor X must equal 0

• to find the vertex of curve we use this rule x -coordinate =-b/2a
• in this equation $x^{2} -4$ -0/1 =0 so here x coordinate =0  so its vertex is on y axis