Line segment AB has endpoints A(3, -7) and B(-9,-5). Find the equation of the perpendicular bisector

of AB.

Respuesta :

Answer:

y = 6x + 12

Step-by-step explanation:

We require the midpoint M and slope of AB

Using the midpoint formula, then

M = [ [tex]\frac{1}{2}[/tex] (3 - 9) , [tex]\frac{1}{2}[/tex] (- 7 - 5) ] = (- 3, - 6 )

Calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = A(3, - 7) and (x₂, y₂ ) = B(- 9, - 5)

m = [tex]\frac{-5+7}{-9-3}[/tex] = [tex]\frac{2}{-12}[/tex] = - [tex]\frac{1}{6}[/tex]

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{1}{6} }[/tex] = 6

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 6 , thus

y = 6x + c ← is the partial equation

To find c substitute M(- 3, - 6) into the partial equation

- 6 = - 18 + c ⇒ c = - 6 + 18 = 12

y = 6x + 12 ← equation of perpendicular bisector

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