Question

The net of a square pyramid is shown below: Net of a square pyramid showing 4 triangles and the square base. The square base has side lengths of 2 inches. The height of each triangle attached to the square is 5 inches. The base of the triangle is the side of the square. What is the surface area of the solid?

Answer 1

Answer:

Surface Area = $8\sqrt{26}$ inches²

OR

Surface Area ≈ 24.4 inches²

Step-by-step explanation:

Surface Area = $a^2+2a\sqrt{\frac{a^2}{4} +h^2}$

Where a = 2 inches and h = 5 inches

Surface Area = $(2)^2+2(2)\sqrt{\frac{2^2}{4} + (5)^2}$

Surface Area = $4+4\sqrt{\frac{4}{4} +25}$

Surface Area = $8\sqrt{26}$ inches²

OR

Surface Area ≈ 24.4 inches²

Answer 2

Answer:

24 in²

Step-by-step explanation:

Surface area= Area of square + 4* Area of triangle

Side of square= 2 in

Base of triangle= 2 in

Height of triangle= 5 in

Surface area= 2² + 4*1/2*2*5= 24 in²