Answer:
∠ A ≈ 16.67°
Step-by-step explanation:
Using the Sine rule in Δ ABC
[tex]\frac{a}{sinA}[/tex] = [tex]\frac{c}{sinC}[/tex] , substitute values
[tex]\frac{8}{sinA}[/tex] = [tex]\frac{16}{sin35}[/tex] ( cross- multiply )
16 sinA = 8 sin35° ( divide both sides by 16 )
sin A = [tex]\frac{8sin35}{16}[/tex] , thus
∠ A = [tex]sin^{-1}[/tex] ( [tex]\frac{8sin35}{16}[/tex] ) ≈ 16.67° ( to 2 dec. places )
