Answer: [tex]\bold{b=\pm\sqrt{3p+4ac}}[/tex]
Step-by-step explanation:
[tex]\dfrac{b^2-4ac}{p}=3\\\\\\\text{Multiply both sides by p:}\\b^2-4ac=3p\\\\\\\text{Add 4ac to both sides:}\\b^2=3p+4ac\\\\\\\text{Take the square root of both sides:}\\b=\pm\sqrt{3p+4ac}[/tex]