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Step-by-step explanation:

[tex]1) \: \: \sqrt{x - 4} + x = 6 \: \: \: .....square \: all \\ (x - 4) + {x}^{2} = 36 \: \: \: simplfy \: \: and \: rearrange\\ {x}^{2} + x - 40 = 0 \: \: quadatric \: eq\\ 2)follow \: same \: steps[/tex]

Answer:

the answer is x=5

number two answer is x=7

Step-by-step explanation:

x-4=36+12-x²=0

13x-40-x²=0

-x²-5x-8x+40=0

(x-5)×(x-8)

x=5

this is the number 1 sorry i can explain everything becuse is a lot

x-2=x²-8x+16

-x²+9x-14=0

x²-9x+14=0

x²-2x-7x+14=0

(x-2) (x-7)

x=7

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