i don't get this can some body help me

Step-by-step explanation:
[tex]1) \: \: \sqrt{x - 4} + x = 6 \: \: \: .....square \: all \\ (x - 4) + {x}^{2} = 36 \: \: \: simplfy \: \: and \: rearrange\\ {x}^{2} + x - 40 = 0 \: \: quadatric \: eq\\ 2)follow \: same \: steps[/tex]
Answer:
the answer is x=5
number two answer is x=7
Step-by-step explanation:
x-4=36+12-x²=0
13x-40-x²=0
-x²-5x-8x+40=0
(x-5)×(x-8)
x=5
this is the number 1 sorry i can explain everything becuse is a lot
x-2=x²-8x+16
-x²+9x-14=0
x²-9x+14=0
x²-2x-7x+14=0
(x-2) (x-7)
x=7