Answer:
For x = 10, the lines will be parallel
Step-by-step explanation:
For parallel lines in a triangle, their sides must be proportional
And,
[tex]\frac{x+4}{x-3} = \frac{x+10}{x}[/tex]
Cross Multiplying
=> x(x+4) = (x-3)(x+10)
=> [tex]x^2+4x = x^2+7x-30[/tex]
=> [tex]x^2-x^2+7x-4x = 30\\[/tex]
=> 3x = 30
Dividing both sides by 3
=> x = 10
