Answer: D. x = 2.16
Step-by-step explanation:
The given equation is [tex]4^x= 20[/tex]
Taking log on both sides, we get
[tex]\log 4^x =\log 20[/tex]
Using properties of logarithm
[tex]\log a^b=b\loga[/tex]
We have,
[tex]x\log 4= \log 20\\\\\Rightarrow\ x=\dfrac{\log 20}{\log 4}\\\\\Rightarrow\ x=\log \dfrac{1.3010}{0.6021} \\\\\Rightarrow\ x= 2.1608\approx 2.16[/tex]
Hence, the solution to the given equation is x = 2.16.
So the correct option is D.
