Question

please help i attached the question as a picture

Answer 1

Answer:

0, 1, and 4

Step-by-step explanation:

Since the denominator of a fraction must not be 0 or it would be undefined, when the denominator is 0 is where you will find your restrictions:

$x^3-5x^2+4x=0 \\\\x(x^2-5x+4)=0 \\\\x(x-1)(x-4)=0$

Therefore, by the zero product property, the restrictions are 0, 1, and 4. Hope this helps!

Answer 2

Answer:

X cannot equal 0,1,4

Step-by-step explanation:

The restrictions are when the denominator goes to zero

x^3 -5x^2 +4x

Factor an x

x( x^2 -5x+4)

x( x-4) (x-1)

Set each term to zero

x=0  x-4 =0   x-1=0

x=0  x=4   x=1

X cannot equal 0,1,4