Question

2) metal bar has a length of 3.0cm a width of 3.0cm and a height of 2.0 cm what is the volume of the water in liters would the bar displace.

Answer 1

Volume = 3.0 x 3.0 x 2.0 => 18.0 cm³

1 L ------------- 1000 cm³
? --------------- 18.0 cm³

Volume = 18 x 1 / 1000

Volume = 18 / 1000

V = 0.018 cm³

hope this helps!

Answer 2

Answer:

0.0180 is the volume of the water in liters would the bar displace.

Explanation:

The length metal bar = l = 3.0 cm

The width metal bar = w =3.0 cm

The height metal bar = h = 2.0 cm

Volume of the cuboid = $l\times w\times h$

Volume of the metal bar = V

$V=l\times w\times h=3.0 cm\times 3.0 cm\times 2.0 cm=18.0 cm^3$

$1 cm^3= 1 mL$

$18.0 cm^3=18.0 mL$

1 mL = 0.001 L

$18.0 mL= 18.0 \times 0.001 L=0.0180 L$

0.0180 is the volume of the water in liters would the bar displace.