Question

What is the perimeter of the polygon in the diagram?

A) 2√(a-b)^2

B) 4(a+b)^2

C) 2(a^2 + b^2)

D) 4√(a^2 + b^2)

Answer 1

we are given a figure that is projected to be a rhombus that is a quadrilateral that has 4 equal sides. in this case, the length of the sides is equal to sqrt (a2 + b2) through the distance formula. There are four equal sides so the perimeter is equal to D) 4√(a^2 + b^2)

Answer 2

Since a rhombus has four (4) equal sides, the perimeter of this polygon is equal to D. 4√(a² + b²).

How to calculate the perimeter of this polygon?

By critically observing the polygon, we can logically deduce that it's a rhombus and it has 4 equal sides.

By applying the distance formula, the side lengths are given by:

S = √(a² + b²)

Since a rhombus has four (4) equal sides, the perimeter is given by this equation:

P = 4S

P = 4√(a² + b²).

Read more on distance formula here: https://brainly.com/question/1418394

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