Question

A body is projected from a point P with an initial speed of 30m/s, at an angle 65° to the horizontal. what is the vertical distance at the time when the horizontal distance is 45 m?

Answer 1

Answer:

Vx = 30 * cos 65 = 12.7 m/s    initial horizontal speed

Vy = 30 * sin 65 = 27.2 m/s    initial vertical speed

t = 45 / 12.7 = 3.54 s     time to travel horizontal distance of 45 m

h = vy t - 1/2 g t^2      height after time t

h = 27.2 * 3.54 - 1/2 * 9.8 * 3.54^2 = 34.9 m