Respuesta :
Given that,
Mass of water = 1.26 kg
Latent heat of vaporization of water [tex]L=2.26\times10^{6}\ J/kg[/tex]
We need to calculate the latent heat
Using formula of latent heat
[tex]Q=mL[/tex]
Where, Q = energy
m = mass
L = latent heat of vaporization
Put the value into the formula
[tex]Q=1.26\times2.26\times10^{6}[/tex]
[tex]Q=2847600\ J[/tex]
[tex]Q=2.84\times10^{6}\ J[/tex]
The temperature changes liquid to steam.
So, The temperature will be increases.
Hence, The latent heat is [tex]2.84\times10^{6}\ J[/tex] and temperature increases.