Question

3x-4x-4-x+65=83x-8x+50

Answer 1

Answer:

$x=\frac{1}{7}$

Step-by-step explanation:

$3x-4x-4-x+65=83x-8x+50$

$3x-4x-x-4+65=83x-8x+50$

$-2x-4+65=83x-8x+50$

$-2x+61=83x-8x+50$

$-2x+61=75x+50$

$-2x+61-61=75x+50-61$

$-2x=75x-11$

$-2x-75x=75x-11-75x$

$-77x=-11$

$\frac{-77x}{-77}=\frac{-11}{-77}$

$x=\frac{1}{7}$

Answer 2

Answer:

x=1/7

Step-by-step explanation:

3x-4x-4-x+65=83x-8x+50

Solving the right side of equation we have;

83x-8x+50 = 75x +50

Solving the left side of the equation we have;

3x-4x-4-x+65= -2x +61

Equating left side and right side.

-2x +61= 75x +50

by grouping terms with x , we have :

-2x- 75x = -61+50

-77x= -11

x= -11/ -77 = 1/7