Question

An iron nail with a mass of 12 g absorbs 12 J of heat.
If the nail was initially at 25° C, what is the final temperature? help!

Answer 1

Answer:

27.25°C

Explanation:

hello,

this question involves heat transfer in an object and to find the final temperature, we'll use formula for heat transfer

data;

mass = 12g

heat energy (Q) = 12J

initial temperature (T1) = 25°C

final temperature (T2) = x

specific heat capacity (c) = 0.444J/g°C

heat energy(Q) = mcΔt

Q = mc(T2 - T1)

$12 = 12*0.444*(x - 25)\\12 = 5.328x - 133.2\\collect like terms\\12 + 133.2 = 5.328x\\145.2 = 5.328x\\divide both sides by 5.328 and solve for x\\x = 145/5.328\\x = 27.25C$

the final temperature was 27.25°C

Answer 2

The final temperature should be considered as the 27.25°C.

Calculation of the final temperature:

Since

mass = 12g

heat energy (Q) = 12J

initial temperature (T1) = 25°C

final temperature (T2) = x

specific heat capacity (c) = 0.444J/g°C

heat energy(Q) = mcΔt

Q = mc(T2 - T1)

So

12 = 12 * 0.444 * (x -25)

12 = 5.328x - 133.2

12 + 133.2 = 5.328x

So x = 27.25

Hence, The final temperature should be considered as the 27.25°C.

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