Part 3. Identify the X intercepts for
y = (x+4)^2-9
![Part 3 Identify the X intercepts fory x429 class=](https://us-static.z-dn.net/files/d4a/6fb48d310dea5ac3a8a960c192b9aecd.jpg)
Answer:
x = -1 or x = -7
Step-by-step explanation:
y = (x + 4)^2 - 9
To find x-intercept, set y = 0
=> (x + 4)^2 - 9 = 0
=> ( x + 1)( x + 7) = 0
=> x = -1 or x = -7
To find the x intercepts, plug in y = 0 and solve for x
y = (x+4)^2 - 9
0 = (x+4)^2 - 9 ... replace y with 0
9 = (x+4)^2
(x+4)^2 = 9
x+4 = plus/minus sqrt(9)
x+4 = sqrt(9) or x+4 = -sqrt(9)
x+4 = 3 or x+4 = -3
x = 3-4 or x = -3-4
-----------------------------------------------------------------
Checking each answer:
Plug x = -1 into the original equation. You should get y = 0 as a result
y = (x+4)^2 - 9
y = (-1+4)^2 - 9
y = (3)^2 - 9
y = 9-9
y = 0 .... so this confirms x = -1 as a solution
The same should apply for the other potential solution x = -7
y = (x+4)^2 - 9
y = (-7+4)^2 - 9
y = (-3)^2 - 9
y = 9-9
y = 0 .... this confirms x = -7 as well