A patient ingests 5 grams of a certain drug which
dissolves away at a constant rate of 10% per hour.
How long will it take before there is only one gram
left?

Respuesta :

If the drug dissolves at a 10% per hour then it will take 131 hours to reach to1 gm because it forms a geometric progression.

What is a geometric progression?

It is a type of sequence in which there is a common ratio.

How to find time?

The dissolution of drug forms a geometric progression where first term is 5 gm and the common ratio is 0.99 and we have to find the value of n for nth term=1 gm

an th term=[tex]ar^{n-1}[/tex]

1=5[tex]0.99^{n-1}[/tex]

0.2=[tex]0.99^{n-1}[/tex]

finding the value of power off 0.99 we found it will be equal to 130 then the value of n will be 130+1=131 hours

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