f(x)=x^2-2x+3; f(x)=-2x+28
![fxx22x3 fx2x28 class=](https://us-static.z-dn.net/files/d9d/6779c6068e5cadd8e7d095e0b14ab175.png)
Answer:
(-5, 38) and
(5,18)
Step-by-step explanation:
[tex]x^2-2x+3=-2x+28\\<=> x^2-2x+3+2x=28\\<=> x^2 = 28-3=25\\<=> x^2-25=0\\<=> x^2-5^2 =0\\<=> (x-5)(x+5)=0\\<=> x = 5 \ or \ x=-5[/tex]
so the solutions are
(-5, 38) and
(5,18)