Answer:
The answer is "Option A"
Explanation:
Given:
Moles in [tex]NaOH = 0.50[/tex]
The equation formula for [tex]NaOH[/tex]and[tex]H_2SO_4[/tex] reactions as follows:
[tex]2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O[/tex]
The reaction's stoichiometry:
If 2 moles of [tex]NaOH[/tex] react with 1 [tex]H_2SO_4[/tex] mole
Thus 0.50 [tex]NaOH[/tex] moles react with = [tex]\frac{1}{2} \times 0.50[/tex] [tex]H_2SO_4[/tex] moles
So, the final value is= 0.25