Answer:
6 adult tickets
39 student tickets
Step-by-step explanation:
let the no. adults be x and the students be y
so, no. of adults + no. of students =45
in other words x+y=45 (make this your 1st equation)
and make 13x+5y=273 your 2nd equation
now lets go back to the 1st eq and make x its subject so this is what it will look like,
x=45-y
now if we take this value of x from the 1st eq and put it in place of the x in the 2nd eq the the 2nd eq looks like this,
13(45-y) +5y =273
now if we solve this it comes
y=39
13(45-y) +5y =273
585 -13y +5y =273
-13y +5y =273 -585
-18y = -312
y = [tex]\frac{-312}{-8}[/tex] (cancel out the minuses)
y = [tex]\frac{312}{8}[/tex]
y=39
now as you know the value of y (no. of students), you can put this value of y in the 1st eq to find the value of x
so x= 45 -y will become
x= 45 -39 (as you know the value of y)
now if we solve this the value of x comes
x=6
hence the no. of adults are 6 and the no. of students are 39.
hope it helped