goldsabrina goldsabrina

20-06-2020
Mathematics

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Solve for n : 21k 3n + 9p >3p+12

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Аноним Аноним

25-06-2020

Answer:

n>[tex]\frac{-6p+12}{63k}[/tex]

Step-by-step explanation:

21k3n>3p-9p+12

21k3n>-6p+12

3n>[tex]\frac{-6p+12}{21k}[/tex]

n>[tex]\frac{-6p+12}{63k}[/tex]

Are you sure you typed the question correctly? like is there supposed to be something between the 21k and the 3n?

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