Respuesta :
Answer and Explanation:
Available data:
- Crooked wings (cw) is caused by a recessive mutant gene that independently assorts with a recessive gene for hairy (h) body.
- Cross between a fly with normal wings and a hairy body and a fly with crooked wings and normal body hair.
- All F1 flies from this cross were wild-type, and these flies were crossed among each other to produce 1024 F2 offspring.
As the whole F1 progeny were wild type, we can assume that their parents were homozygous for their respective traits. This is:
First cross:
Parental) CWCW hh x cwcw HH
Gametes) CWh CWh CWh CWh
cwH cwH cwH cwH
F1) 100% CWcw Hh
Second cross:
Parental) CWcw Hh x CWcw Hh
Gametes) CWH CWh cwH cwh
CWH CWh cwH cwh
Punnet square) CWH CWh cwH cwh
CWH CWCWHH CWCWHh CWcwHH CWcwHh
CWh CWCWHh CWCWhh CWcwHh CWcwhh
cwH CWcwHH CWcwHh cwcwHH cwcwHh
cwh CWcwHh CWcwhh cwcwHh cwcwhh
F2) 1024 Individuals
- 9/16 CW- H-, individuals with normal wings and normal body hair
- 3/16 CW- hh, individuals with normal wings and hairy body
- 3/16 cwcw H-, individuals with Crooked wings and normal body hair
- 1/16 cwcw hh, individuals with Crooked wings and hairy body
To calculate how many individuals of each phenotype would be in the F2, we can perform a three simple rule:
16 ------ 100% of the offspring ------ 1024 individuals
9 ------- 56.25% of the offspring ---- 576 individuals
3 ------- 18.75% of the offspring ----- 192 individuals
3 ------- 18.75% of the offspring ----- 192 individuals
1 -------- 6.25% of the offspring ----- 64 individuals.
Of the total 1024 individuals,
- 576 (9/16) would have normal wings and normal body hair, CW-H-.
- 192 (3/16) would have normal wings and hairy body, CW- hh.
- 192 (3/16) would have crooked wings and normal body hair, cwcwH-.
- 64 (1/16) would have crooked wings and hairy body, cwcw hh.