Question

Forty adult men in the United States are randomly selected and measured for their body mass index​ (BMI). Based on that​ sample, it is estimated that the average​ (mean) BMI for men is 25.5​, with a margin of error of 3.3. Use the given statistic and margin of error to identify the range of values​ (confidence interval) likely to contain the true value of the population parameter

Answer 1

Answer:

$25.5 -3.3= 22.2$

$25.5 +3.3= 28.8$

And the confidence interval would be given by: $22.2\leq \mu \leq 28.8$

Step-by-step explanation:

$\bar X=25.5$ represent the sample mean for the sample  

ME= 3.3 represent the margin of error

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$   (1)

The margin of error is given by;

$ME =t_{\alpha/2}\frac{s}{\sqrt{n}}= 3.3$

And the confidence interval would be given by:

$25.5 -3.3= 22.2$

$25.5 +3.3= 28.8$

And the confidence interval would be given by: $22.2\leq \mu \leq 28.8$