Answer:
The answer is "2.5 mole"
Explanation:
The reaction for producing [tex]NH_3[/tex] can be defined as follows:
Reaction:
[tex]N_2+ 3H_2 \rightarrow 2NH_3[/tex]
According to the above reaction, to produce 2 moles of [tex]NH_3[/tex] we need 1 mole of nitrogen:
So, according to the question to produce 5.0 mole [tex]NH_3[/tex] the required [tex]N_2[/tex]:
[tex]\Rightarrow \ 5.0 \ mole \ of \ NH_3 \times \frac{1 \ mole\ of \ N_2}{2 \ mole \ of NH_3}\\\\\Rightarrow 5.0 \times \frac{1}{2}\\\\\Rightarrow 2.5\ mole\\[/tex]
To produce 5.0 mole [tex]NH_3[/tex] we need 2.5 mole [tex]N_2[/tex]