Question

Please help! For the function f(x) = 2x^6 + 3x^4 - 4x^3 + (1/x) - sin(2x) find the first four derivatives.

Answer 1

Answer:

Step-by-step explanation:

First derivative

$12x^5+12x^3 -x^{-2}-2cos (2x)$

Second derivative

$60x^4+36x^2+2x^{-3}+4sin(2x)$

Third derivative

$240x^3+72x-6x^{-4}+8cos(2x)$

Fourth derivative

$720x^2+72+24x^{-5}-16sin(2x)$