Answer:
295.4 J.
Explanation:
From the question,
The net work done on the block = work done against friction minus the work done on the block to move it across the frozen lake.
W = (FcosФ-F')d........................ Equation 1
Where W = total work done on the block, F' = force of friction, d = distance, F = force applied to the block, Ф = angle between the force and the horizontal, d = distance.
Given: F' = 12.6 N, F = 46.5 N, d = 10 m, Ф = 25°
Substitute into equation equation 1
W = (46.5cos25°-12.6)10
W = (42.14-12.6)10
W = 295.4 J.
