Answer:
We will have 2 products
a) hexan-3-one
b) hexan-2-one
Explanation:
We have to remember that this reaction will produce a ketone (with a previous enol formation). Additionally, this reaction is a markovnikov reaction, so the C=O group would be added in the most substituted carbon, but in this case, in the triple bond, we have the same substitution, both carbons in the triple bond are secondary carbons. So, we will have two products, the C=O group be added in the left carbon of the triple bond and the right carbon of the triple bond.
See figure 1
I hope it helps!