Respuesta :

Answer:

-6 ≤x

Step-by-step explanation:

3x-2≤5(x+2)

Distribute

3x-2≤5x+10

Subtract 3x

3x-2-3x≤5x +10-3x  

-2 ≤2x+10

Subtract 10 from each side

-2-10 ≤2x+10-10

-12 ≤2x

Divide by 2

-12/2≤2x/2

-6 ≤x

Answer:

Step-by-step explanation:

You have to first use the distributive property of 5(x+2)

That would be 5x+10.

So it would be all together

[tex]3x-2\leq 5x+2[/tex]

to see if it is true

x=2

6-2

[tex]6-2\leq 10+2\\4\leq 12[/tex]

it is true

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