Respuesta :
Answer:
-6 ≤x
Step-by-step explanation:
3x-2≤5(x+2)
Distribute
3x-2≤5x+10
Subtract 3x
3x-2-3x≤5x +10-3x
-2 ≤2x+10
Subtract 10 from each side
-2-10 ≤2x+10-10
-12 ≤2x
Divide by 2
-12/2≤2x/2
-6 ≤x
Answer:
Step-by-step explanation:
You have to first use the distributive property of 5(x+2)
That would be 5x+10.
So it would be all together
[tex]3x-2\leq 5x+2[/tex]
to see if it is true
x=2
6-2
[tex]6-2\leq 10+2\\4\leq 12[/tex]
it is true