Question

Algebra 2 Help!

What are the sine, cosine, and tangent of 5pi/3 radians?

sin Θ = -sqrt 3/2; cos Θ = 1/2; tan Θ = -sqrt 3

sin Θ = sqrt 3/2; cos Θ = -1/2; tan Θ = sqrt 3

sin Θ = sqrt 3/2; cos Θ = 1/2; tan Θ = sqrt 3

sin Θ = -sqrt 3/2; cos Θ = -1/2; tan Θ = -sqrt 3

Answer 1

Base on the question that ask to calculate the sine, cosine, and tangent of 5pi/3 radians and base on my further calculation, I would say that the answer would be sin Θ = -sqrt 3/2; cos Θ = -1/2; tan Θ = -sqrt 3. I hope you are satisfied with my answer and feel free to ask for more if you have question and further clarification 

Answer 2

Answer:

$sin(\frac{5\pi }{3})=-\frac{\sqrt{3}}{2}$ ; $cos(\frac{5\pi }{3})=\frac{1}{2}$ ; $tan(\frac{5\pi }{3})=-\sqrt{3}$

Step-by-step explanation:

we know that

$\pi \ radians=180\ degrees$

so

$\frac{5\pi }{3}\ radians=300\ degrees$

The angle belong to the IV quadrant

therefore

The sine is negative

The cosine is positive

The tangent is negative

$360\°-300\°=60\°$

so

$sin(\frac{5\pi }{3})=-sin(60\°)=-\frac{\sqrt{3}}{2}$

$cos(\frac{5\pi }{3})=cos(60\°)=\frac{1}{2}$

$tan(\frac{5\pi }{3})=-tan(60\°)=-\sqrt{3}$