Answer:
12ft [tex]\times[/tex]7ft [tex]\times[/tex]6ft
Step-by-step explanation:
Given that truck can hold = 504 [tex]ft^{3}[/tex] i.e.
Volume, V = 504 [tex]ft^{3}[/tex]
Length of cargo space = 12 ft
Let width of cargo space = w ft
As per question statement:
Let height of cargo space = (w-1) ft
To find: The Dimensions of Cargo Space
Formula for Volume of Cargo Space:
V = Length [tex]\times[/tex] Width [tex]\times[/tex] Height
Putting the given values and conditions:
504 = 12 [tex]\times[/tex] [tex]w \times (w-1)[/tex]
[tex]\Rightarrow w(w-1) = \dfrac{504}{12}\\\Rightarrow w^{2} -w = 42\\\Rightarrow w^{2} -w - 42=0\\\Rightarrow w^{2} -7w +6w -42 =0\\\Rightarrow w(w -7) +6(w -7) =0\\\Rightarrow (w -7)(w+6) = 0\\\Rightarrow w =7, -6[/tex]
Dimensions can not be negative, so width, w = 7 ft
Height = (w-1) = 7-1 = 6 ft
So, the dimensions are 12ft [tex]\times[/tex]7ft [tex]\times[/tex]6ft.