Respuesta :

Answer:

6.347 g Zinc to the nearest thousandth.

Step-by-step explanation:

Using the molar atomic mass of the elements:

65.38 g Zinc produces 65.38 + 2(16 + 1.008) = 99.396 g Zn(OH)2

So by proportion  amount of zinc required to produce 9,65 g Zn(OH)2

= (65.38/99.396) * 9.65 g Zinc

= 0.65777 * 9.65

= 6.347g Zinc.

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